Red Huang

Red Huang

Codeforces 第179轮(第二组)C. Greg 和数组

利用两个线段树更新即可

虽然不是正解 速度有待加强,不过练练线段树也不错

//  
//        GGGGGGGGGGGGG        CCCCCCCCCCCCC               AAA  
//     GGG::::::::::::G     CCC::::::::::::C              A:::A  
//   GG:::::::::::::::G   CC:::::::::::::::C             A:::::A  
//  G:::::GGGGGGGG::::G  C:::::CCCCCCCC::::C            A:::::::A  
// G:::::G       GGGGGG C:::::C       CCCCCC           A:::::::::A  
//G:::::G              C:::::C                        A:::::A:::::A  
//G:::::G              C:::::C                       A:::::A A:::::A  
//G:::::G    GGGGGGGGGGC:::::C                      A:::::A   A:::::A  
//G:::::G    G::::::::GC:::::C                     A:::::A     A:::::A  
//G:::::G    GGGGG::::GC:::::C                    A:::::AAAAAAAAA:::::A  
//G:::::G        G::::GC:::::C                   A:::::::::::::::::::::A  
// G:::::G       G::::G C:::::C       CCCCCC    A:::::AAAAAAAAAAAAA:::::A  
//  G:::::GGGGGGGG::::G  C:::::CCCCCCCC::::C   A:::::A             A:::::A  
//   GG:::::::::::::::G   CC:::::::::::::::C  A:::::A               A:::::A  
//     GGG::::::GGG:::G     CCC::::::::::::C A:::::A                 A:::::A  
//        GGGGGG   GGGG        CCCCCCCCCCCCCAAAAAAA                   AAAAAAA  
#include <iostream>  
#include <cstdio>  
#include <cstring>  
#include <algorithm>  
#include <cmath>  
#include <climits>  
#include <vector>  
#include <set>  
#include <map>  
#include <queue>  
#include <cctype>  
#include <utility>  
#include <ctime>  
using namespace std;  
#ifdef DEBUG  
#define VAR(a,b) decltype(b) a=(b)  
#define debug(...) printf("DEBUG: "),printf(__VA_ARGS__)  
#define gettime() end_time=clock();printf("now running time is %.7f\\n",(float)(end_time - start_time)/CLOCKS_PER_SEC);  
#else  
#define VAR(a,b) __typeof(b) a=(b)  
#define debug(...)  
#define gettime()  
#endif  
typedef unsigned int uint;  
typedef long long int Int;  
typedef unsigned long long int UInt;  
#define Set(a,s) memset(a,s,sizeof(a))  
#define Write(w) freopen(w,"w",stdout)  
#define Read(r) freopen(r,"r",stdin)  
#define Pln() printf("\\n")  
#define I_de(x,n)for(int i=0;i<n;i++)printf("%d ",x[i]);Pln()  
#define De(x)printf(#x"%d\\n",x)  
#define For(i,x)for(int i=0;i<x;i++)  
#define CON(x,y) x##y  
#define Pmz(dp,nx,ny)for(int hty=0;hty<ny;hty++){for(int htx=0;htx<nx;htx++){\\  
    printf("%d ",dp[htx][hty]);}Pln();}  
#define M 100005  
#define PII pair<int,int>  
#define PB push_back  
#define oo INT_MAX  
#define Set_oo 0x3f  
#define FOR(a,b) for(VAR(a,(b).begin());a!=(b).end();++a)  
#define eps 1e-6  
#define X first  
#define Y second  
clock_t start_time=clock(), end_time;  
bool xdy(double x,double y){return x>y+eps;}  
bool xddy(double x,double y){return x>y-eps;}  
bool xcy(double x,double y){return x<y-eps;}  
bool xcdy(double x,double y){return x<y+eps;}  
int min3(int x,int y,int z){  
    int tmp=min(x,y);  
    return min(tmp,z);  
}  
int max3(int x,int y,int z){  
    int tmp=max(x,y);  
    return max(tmp,z);  
}  
#define lson(x) (x<<1)  
#define rson(x) (x<<1|1)  
struct tree{  
    Int v[M*4];  
    int mode;  
    tree(){  
        Set(v,0);  
        mode=0;  
    }  
    void init(){  
        Set(v,0);  
        mode=0;  
    }  
    void push_down(int index){  
        v[lson(index)]+=v[index];  
        v[rson(index)]+=v[index];  
        v[index]=0;  
    }  
    void update(int index,int l,int r,int bl,int br,Int add){  
        if(l<=bl&&br<=r){  
            v[index]+=add;  
            return ;  
        }  
        push_down(index);  
        int mid=(br+bl)>>1;  
        if(r<=mid){  
            update(lson(index),l,r,bl,mid,add);  
        }else if(l>mid){  
            update(rson(index),l,r,mid+1,br,add);  
        }else{  
            update(lson(index),l,mid,bl,mid,add);  
            update(rson(index),mid+1,r,mid+1,br,add);  
        }  
    }  
    void query(int index,int bl,int br,Int a[]){  
        if(bl==br){  
            if(mode){  
                a[bl]=a[bl]*v[index];  
            }else a[bl]+=v[index];  
            return;  
        }  
        push_down(index);  
        int mid=(bl+br)>>1;  
        query(lson(index),bl,mid,a);  
        query(rson(index),mid+1,br,a);  
    }  
};  
int n,m,k;  
int l[M],r[M];  
Int d[M];  
Int a[M];  
tree instree,anstree;  
int main() {  
    ios_base::sync_with_stdio(0);  
    while(~scanf("%d%d%d",&n,&m,&k)){  
        instree.init();  
        anstree.init();  
        for(int i=1;i<=n;i++)scanf("%I64d",&a[i]);  
        for(int i=1;i<=m;i++){  
            scanf("%d%d%I64d",&l[i],&r[i],&d[i]);  
//            instree.update(1,i,i,1,m,1);  
        }  
        for(int i=0;i<k;i++){  
            int x,y;  
            scanf("%d%d",&x,&y);  
            instree.update(1,x,y,1,m,1);  
        }  
        instree.mode=1;  
        instree.query(1,1,m,d);  
        for(int i=1;i<=m;i++){  
//            debug("%I64d\\n",d[i]);  
            anstree.update(1,l[i],r[i],1,n,d[i]);  
        }  
        anstree.query(1,1,n,a);  
        for(int i=1;i<=n;i++)printf("%I64d ",a[i]);  
        Pln();  
    }  
}  
加载中...
此文章数据所有权由区块链加密技术和智能合约保障仅归创作者所有。