非常に面倒な実装問題で、このような問題はすべての状況を if 文で表現する必要があります。
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#line 5 "GCAcode.cpp"
#include <cstdlib>
#include <cctype>
#include <cstring>
#include <cstdio>
#include <cmath>
#include <algorithm>
#include <vector>
#include <string\>
#include <iostream>
#include <sstream>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <fstream>
#include <numeric>
#include <iomanip>
#include <bitset>
#include <list>
#include <stdexcept>
#include <functional>
#include <utility>
#include <ctime>
using namespace std;
#ifdef DEBUG
#define VAR(a,b) \_\_typeof(b) a=(b)
#define debug(...) printf("DEBUG: "),printf(\_\_VA\_ARGS\_\_)
#else
#define VAR(a,b) \_\_typeof(b) a=(b)
#define debug(...)
#endif
typedef unsigned int uint;
typedef long long int Int;
typedef unsigned long long int UInt;
#define Set(a,s) memset(a,s,sizeof(a))
#define Pln() printf("\\n")
#define For(i,x)for(int i=0;i<x;i++)
#define CON(x,y) x##y
#define M MAX\_LIMITS
#define PB push\_back
#define oo INT\_MAX
#define FOR(a,b) for(VAR(a,(b).begin());a!=(b).end();++a)
#define eps 1e-9
#define X first
#define Y second
inline bool xdy(double x,double y){return x>y+eps;}
inline bool xddy(double x,double y){return x>y-eps;}
inline bool xcy(double x,double y){return x<y-eps;}
inline bool xcdy(double x,double y){return x<y+eps;}
const Int mod=1000000007;
class WaterLevel
{
public:
double netAmt(int evapNormal, int evapFlood, vector <int\> rain)
{
double now=0;
double part=1.;
for(int i=0;i<rain.size();){
if(now==0){//中央
double t=rain\[i\]\*part-evapNormal\*part;
if(t<=0){
now+=t;
}
else{
t=rain\[i\]\*part-evapFlood\*part;
if(t>0){
now+=t;
}else{
now=0;
}
}
part=1.;
i++;
}else if(now<0){
double t=rain\[i\]\*part-evapNormal\*part;
if(t+now>=0){//洪水段に達することができる
part=1-(-now/t);
now=0;
}else{
now+=t;
part=1.;
i++;
}
}else{//現在洪水段を超えている
double t=rain\[i\]\*part-evapFlood\*part;
if(t+now<=0){
part=(1-(-now)/t);
now=0;
}else{
now+=t;
part=1.;
i++;
}
}
printf("%.2f %d\\n",now,i);
}
return now;
}
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public:
void run\_test(int Case) { if ((Case == -1) || (Case == 0)) test\_case\_0(); if ((Case == -1) || (Case == 1)) test\_case\_1(); if ((Case == -1) || (Case == 2)) test\_case\_2(); if ((Case == -1) || (Case == 3)) test\_case\_3(); if ((Case == -1) || (Case == 4)) test\_case\_4();}
private:
template <typename T> string print\_array(const vector<T> &V) { ostringstream os; os << "{ "; for (typename vector<T>::const\_iterator iter = V.begin(); iter != V.end(); ++iter) os << '\\"' << \*iter << "\\","; os << " }"; return os.str(); }
void verify\_case(int Case, const double &Expected, const double &Received) { cout << "テストケース #" << Case << "..."; if (Expected == Received) cout << "合格" << endl; else { cout << "不合格" << endl; cout << "\\t期待値: \\"" << Expected << '\\"' << endl; cout << "\\t受け取った値: \\"" << Received << '\\"' << endl; } }
void test\_case\_0() { int Arg0 = 20; int Arg1 = 40; int Arr2\[\] = {0,60,0,0}; vector <int\> Arg2(Arr2, Arr2 + (sizeof(Arr2) / sizeof(Arr2\[0\]))); double Arg3 = -35.0; verify\_case(0, Arg3, netAmt(Arg0, Arg1, Arg2)); }
void test\_case\_1() { int Arg0 = 20; int Arg1 = 39; int Arr2\[\] = {0,60}; vector <int\> Arg2(Arr2, Arr2 + (sizeof(Arr2) / sizeof(Arr2\[0\]))); double Arg3 = 10.5; verify\_case(1, Arg3, netAmt(Arg0, Arg1, Arg2)); }
void test\_case\_2() { int Arg0 = 20; int Arg1 = 40; int Arr2\[\] = {0}; vector <int\> Arg2(Arr2, Arr2 + (sizeof(Arr2) / sizeof(Arr2\[0\]))); double Arg3 = -20.0; verify\_case(2, Arg3, netAmt(Arg0, Arg1, Arg2)); }
void test\_case\_3() { int Arg0 = 200; int Arg1 = 800; int Arr2\[\] = {0,600}; vector <int\> Arg2(Arr2, Arr2 + (sizeof(Arr2) / sizeof(Arr2\[0\]))); double Arg3 = 0.0; verify\_case(3, Arg3, netAmt(Arg0, Arg1, Arg2)); }
void test\_case\_4() { int Arg0 = 300; int Arg1 = 379; int Arr2\[\] = {0, 800, 0, 800, 512, 555, 1000}; vector <int\> Arg2(Arr2, Arr2 + (sizeof(Arr2) / sizeof(Arr2\[0\]))); double Arg3 = 0.0; verify\_case(4, Arg3, netAmt(Arg0, Arg1, Arg2)); }
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};
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int main()
{
WaterLevel \_\_\_test;
\_\_\_test.run\_test(-1);
return 0;
}
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