Red Huang

Red Huang

uva 10818

這題非常的複雜 + 麻煩,需要用到 BFS+Hamilton Path+DP

//  
//        GGGGGGGGGGGGG        CCCCCCCCCCCCC               AAA  
//     GGG::::::::::::G     CCC::::::::::::C              A:::A  
//   GG:::::::::::::::G   CC:::::::::::::::C             A:::::A  
//  G:::::GGGGGGGG::::G  C:::::CCCCCCCC::::C            A:::::::A  
// G:::::G       GGGGGG C:::::C       CCCCCC           A:::::::::A  
//G:::::G              C:::::C                        A:::::A:::::A  
//G:::::G              C:::::C                       A:::::A A:::::A  
//G:::::G    GGGGGGGGGGC:::::C                      A:::::A   A:::::A  
//G:::::G    G::::::::GC:::::C                     A:::::A     A:::::A  
//G:::::G    GGGGG::::GC:::::C                    A:::::AAAAAAAAA:::::A  
//G:::::G        G::::GC:::::C                   A:::::::::::::::::::::A  
// G:::::G       G::::G C:::::C       CCCCCC    A:::::AAAAAAAAAAAAA:::::A  
//  G:::::GGGGGGGG::::G  C:::::CCCCCCCC::::C   A:::::A             A:::::A  
//   GG:::::::::::::::G   CC:::::::::::::::C  A:::::A               A:::::A  
//     GGG::::::GGG:::G     CCC::::::::::::C A:::::A                 A:::::A  
//        GGGGGG   GGGG        CCCCCCCCCCCCCAAAAAAA                   AAAAAAA  
#include <iostream>  
#include <cstdio>  
#include <cstring>  
#include <algorithm>  
#include <cmath>  
#include <climits>  
#include <vector>  
#include <set>  
#include <map>  
#include <queue>  
#include <cctype>  
#include <utility>  
#include <ctime>  
using namespace std;  
#ifdef DEBUG  
#define VAR(a,b) decltype(b) a=(b)  
#define debug(...) printf("DEBUG: "),printf(\_\_VA\_ARGS\_\_)  
#define gettime() end\_time=clock();printf("now running time is %.7f\\n",(float)(end\_time - start\_time)/CLOCKS\_PER\_SEC);  
#else  
#define VAR(a,b) \_\_typeof(b) a=(b)  
#define debug(...)  
#define gettime()  
#endif  
typedef unsigned int uint;  
typedef long long int Int;  
typedef unsigned long long int UInt;  
#define Set(a,s) memset(a,s,sizeof(a))  
#define Write(w) freopen(w,"w",stdout)  
#define Read(r) freopen(r,"r",stdin)  
#define Pln() printf("\\n")  
#define I\_de(x,n)for(int i=0;i<n;i++)printf("%d ",x\[i\]);Pln()  
#define De(x)printf(#x"%d\\n",x)  
#define For(i,x)for(int i=0;i<x;i++)  
#define CON(x,y) x##y  
#define Pmz(dp,nx,ny)for(int hty=0;hty<ny;hty++){for(int htx=0;htx<nx;htx++){\\  
    printf("%d ",dp\[htx\]\[hty\]);}Pln();}  
#define M 25  
#define PII pair<int,int\>  
#define PB push\_back  
#define oo (1<<29)  
#define Set\_oo 0x3f  
#define FOR(a,b) for(VAR(a,(b).begin());a!=(b).end();++a)  
#define eps 1e-6  
#define X first  
#define Y second  
clock\_t start\_time=clock(), end\_time;  
bool xdy(double x,double y){return x>y+eps;}  
bool xddy(double x,double y){return x>y-eps;}  
bool xcy(double x,double y){return x<y-eps;}  
bool xcdy(double x,double y){return x<y+eps;}  
int min3(int x,int y,int z){  
    int tmp=min(x,y);  
    return min(tmp,z);  
}  
int max3(int x,int y,int z){  
    int tmp=max(x,y);  
    return max(tmp,z);  
}  
int nx,ny;  
int bx,by;  
int mz\[M\]\[M\];  
int bnum;  
int buyx\[M\];  
int buyy\[M\];  
int dx\[\]={1,0,0,-1};  
int dy\[\]={0,-1,1,0};  
char dir\[\]="ENSW";  
struct path{  
    int d;  
    char str\[205\];  
};  
path d\[M\]\[M\];  
void go(int b,int e){  
    int bx=buyx\[b\],by=buyy\[b\];  
    int ex=buyx\[e\],ey=buyy\[e\];  
    char rec\[M\]\[M\]\[256\]={};  
    int dis\[M\]\[M\];  
    fill(&dis\[0\]\[0\],&dis\[M-1\]\[M-1\],oo);  
    queue<PII> q;  
    dis\[bx\]\[by\]=0;  
    q.push(PII(bx,by));  
    while(!q.empty()){  
        int x=q.front().X;  
        int y=q.front().Y;  
//        debug("%d %d\\n",x,y);  
        q.pop();  
        for(int i=0;i<4;i++){  
            int nex=x+dx\[i\];  
            int ney=y+dy\[i\];  
            if(nex>=nx||nex<0||ney>=ny||ney<0)continue;  
            if(mz\[nex\]\[ney\]==1)continue;  
            if(dis\[nex\]\[ney\]>dis\[x\]\[y\]+1){  
                dis\[nex\]\[ney\]=dis\[x\]\[y\]+1;  
                int len=strlen(rec\[x\]\[y\]);  
                strcpy(rec\[nex\]\[ney\],rec\[x\]\[y\]);  
                rec\[nex\]\[ney\]\[len\]=dir\[i\];  
                rec\[nex\]\[ney\]\[len+1\]=0;  
                q.push(PII(nex,ney));  
            }  
        }  
    }  
    d\[b\]\[e\].d=dis\[ex\]\[ey\];  
//    printf("%s",rec\[ex\]\[ey\]);  
    strcpy(d\[b\]\[e\].str,rec\[ex\]\[ey\]);  
}  
int dp\[1<<13\]\[20\];  
int rpath\[1<<13\]\[20\];  
int reach;  
int dfs(int s,int now,int dep){  
    if(s==reach){  
        rpath\[s\]\[now\]=0;  
        return (dp\[s\]\[now\]=d\[now\]\[0\].d);  
    }  
//    debug("%d %d %d\\n",dep,s,reach);  
    if(dp\[s\]\[now\]!=-1)return dp\[s\]\[now\];  
    int minans=-1;  
    int index=-1;  
    int t;  
    for(int i=0;i<bnum;i++){  
        if(i!=now&&(!((s>>i)&1))&&d\[now\]\[i\].d!=oo){  
            int h;  
            if((h=dfs(s|(1<<i),i,dep+1))!=0)  
                t=d\[now\]\[i\].d+h;  
            if(minans==-1||t<minans||(t==minans&&strcmp(d\[now\]\[i\].str,d\[now\]\[index\].str)<0)){  
                minans=t;  
                index=i;  
            }  
        }  
    }  
    if(minans<0)minans=0;  
    rpath\[s\]\[now\]=index;  
    return (dp\[s\]\[now\]=minans);  
}  
void printpath(int s,int x){  
    int y=rpath\[s\]\[x\];  
    printf("%s",d\[x\]\[y\].str);  
    if(y==0)return;  
    printpath(s^(1<<y),y);  
}  
void solve(){  
    for(int i=0;i<bnum;i++){  
        for(int j=0;j<bnum;j++){  
            go(i,j);  
//            debug("%d %d %d %s\\n",i,j,d\[i\]\[j\].d,d\[i\]\[j\].str);  
        }  
    }  
    Set(dp,-1);  
    reach=1;  
    for(int i=1;i<bnum;i++){  
        if(d\[0\]\[i\].d<oo)reach|=(1<<i);  
    }  
    if(dfs(1,0,0)){  
        printpath(1,0);  
        Pln();  
    }else printf("Stay home!\\n");  
}  
int main() {  
    ios\_base::sync\_with\_stdio(0);  
    while(~scanf("%d%d%\*c",&ny,&nx)&&nx+ny){  
        bnum=1;  
        char str\[25\];  
        for(int i=0;i<ny;i++){  
            gets(str);  
            for(int j=0;j<nx;j++){  
                if(str\[j\]==' '||str\[j\]=='S')mz\[j\]\[i\]=0;  
                else if(str\[j\]=='\*'){  
                    mz\[j\]\[i\]=2;  
                    buyx\[bnum\]=j;  
                    buyy\[bnum\]=i;  
                    bnum++;  
                }  
                else mz\[j\]\[i\]=1;  
                if(str\[j\]=='S'){  
                    buyx\[0\]=j;  
                    buyy\[0\]=i;  
                }  
            }  
        }  
        solve();  
    }  
  
  
  
  
  
  
  
  
  
  
  
  
  
}  

Loading...
Ownership of this post data is guaranteed by blockchain and smart contracts to the creator alone.